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8b^2+11b=11=6
We move all terms to the left:
8b^2+11b-(11)=0
a = 8; b = 11; c = -11;
Δ = b2-4ac
Δ = 112-4·8·(-11)
Δ = 473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{473}}{2*8}=\frac{-11-\sqrt{473}}{16} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{473}}{2*8}=\frac{-11+\sqrt{473}}{16} $
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